(-x^-2)/3+(x^-1)/2=0

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Solution for (-x^-2)/3+(x^-1)/2=0 equation: 


D( x )

x = 0

-x = 0

x = 0

x = 0

-x = 0

x = 0

x in (-oo:0) U (0:+oo)

(x^-1)/2+((-x)^-2)/3 = 0

1/2*x^-1+1/3*x^-2 = 0

t_1 = x^-1

1/3*t_1^2+1/2*t_1^1 = 0

1/3*t_1^2+1/2*t_1 = 0

DELTA = (1/2)^2-(0*1/3*4)

DELTA = 1/4

DELTA > 0

t_1 = ((1/4)^(1/2)-1/2)/(1/3*2) or t_1 = (-(1/4)^(1/2)-1/2)/(1/3*2)

t_1 = 0 or t_1 = -3/2

t_1 = -3/2

x^-1+3/2 = 0

1*x^-1 = -3/2 // : 1

x^-1 = -3/2

-1 < 0

1/(x^1) = -3/2 // * x^1

1 = -3/2*x^1 // : -3/2

-2/3 = x^1

x = -2/3

t_1 = 0

x^-1+0 = 0

x^-1 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x = -2/3

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